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I was wondering if someone could help me out by cracking this password for me. Hash: e0d8573a8cea194e0151a30bd882d898 Salt: rbIY' Its from IPB, the newest version which I believe is 2.3.4 Any help would be wonderful! Thanks in advance! Posted: Fri Jul 25, 2008 4:21 am Torre Regular user Joined: Jul 24, 2008 Posts: 11 I am willing to pay $20 for this, this is really important to me. Any help would be appreciated. Posted: Fri Jul 25, 2008 10:07 am lenny Valuable expert Joined: May 15, 2008 Posts: 275 Ill get to work cracking this (for free) if sombody could tell me the format of IPB 2.3.4 hashes! (no promises though :p) Posted: Fri Jul 25, 2008 11:06 am pexli Valuable expert Joined: May 24, 2007 Posts: 665 Location: Bulgaria lenny try to learn how to use search in google or in insidepro forum. md5(md5($salt).md5($pass)) Posted: Fri Jul 25, 2008 11:47 am lenny Valuable expert Joined: May 15, 2008 Posts: 275 I did , hence the question. I could only find information on older versions of IPB. Admittedly I didn't think to search the InsidePro forums... Anyway, I am cracking now Posted: Fri Jul 25, 2008 2:19 pm Torre Regular user Joined: Jul 24, 2008 Posts: 11 Thanks much! I can give you a copy of the newest IPB software if you like. Posted: Fri Jul 25, 2008 3:14 pm lenny Valuable expert Joined: May 15, 2008 Posts: 275 Well hang about, I haven't cracked the hash yet :p Edit: On top of that, i have run it through most of my dictionaries to no avail. Still, i haven't started with my 32gb wordlist just yet Posted: Fri Jul 25, 2008 5:27 pm Torre Regular user Joined: Jul 24, 2008 Posts: 11 Thank you so much, lenny! If you need anymore information, please don't hesitate to ask! Posted: Fri Jul 25, 2008 6:45 pm lenny Valuable expert Joined: May 15, 2008 Posts: 275 Hmm...Well all my dictionaries have come up with nothing... I will probably try a combined dictionary attack and a brute force attack... but the chances are looking slimmer and slimmer.... as i said, no promises... then again I may get lucky Edit: Started brute force attack... ~23 hours to go Edit Edit: Any idea of the length of the hash? Do you know *anything* else about the hash? It would help *a lot* Posted: Fri Jul 25, 2008 6:57 pm Torre Regular user Joined: Jul 24, 2008 Posts: 11 Darnit. I hope we can get lucky. Unfortunately, I don't really know anything. I just know that it is from IPB 2.3.4 and the type of encrypting is md5(md5($salt).md5($pass)). Would you like to me to upload a copy of IPB? Posted: Fri Jul 25, 2008 7:06 pm Torre Regular user Joined: Jul 24, 2008 Posts: 11 There is another encryption of this password that I have, but I think it is a little bit more difficult. Hash in Database: 07f972a7bec7e5eee4c42e7f3f4bca26 Method: md5(sha1(md5($password).$blowfish).sha1(sha1(md5($password).$blowfish).$blowfish)); Blowfish: 1 Posted: Fri Jul 25, 2008 7:30 pm lenny Valuable expert Joined: May 15, 2008 Posts: 275 Yeah, that second one is a little more difficult to work with Maybe upload a copy of IPB... Maybe I am missing somthing, or 2.3.4 uses a different method of hashing passwords? Its just a guess, but might explain why it is being a pain to crack and would put me back on track Posted: Fri Jul 25, 2008 7:51 pm Torre Regular user Joined: Jul 24, 2008 Posts: 11 I have uploaded IPB and sent you a PM with the link. Posted: Fri Jul 25, 2008 8:24 pm lenny Valuable expert Joined: May 15, 2008 Posts: 275 Quote: /*-------------------------------------------------------------------------*/ // Authorize against local DB: // $username: Log in username // $password: Plain text password /*-------------------------------------------------------------------------*/ function auth_local( $username, $password ) { $password = md5( $password ); . Hmmmm..... This disturbed me a little... Posted: Fri Jul 25, 2008 8:31 pm Torre Regular user Joined: Jul 24, 2008 Posts: 11 Hmm... I wonder when that is used. I just did a check with my own salt and my own password using the md5(md5($salt).md5($pass)). That must be used for just generating the first part of the hash. (?) Basically what I am saying is the method is md5(md5($salt).md5($pass)). 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